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Copy path443. String Compression.java
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443. String Compression.java
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1557851233
tags:String, Basic Implementation
```
/*
Given an array of characters, compress it in-place.
The length after compression must always be smaller than or equal to the original array.
Every element of the array should be a character (not int) of length 1.
After you are done modifying the input array in-place, return the new length of the array.
Follow up:
Could you solve it using only O(1) extra space?
Example 1:
Input:
["a","a","b","b","c","c","c"]
Output:
Return 6, and the first 6 characters of the input array should be: ["a","2","b","2","c","3"]
Explanation:
"aa" is replaced by "a2". "bb" is replaced by "b2". "ccc" is replaced by "c3".
Example 2:
Input:
["a"]
Output:
Return 1, and the first 1 characters of the input array should be: ["a"]
Explanation:
Nothing is replaced.
Example 3:
Input:
["a","b","b","b","b","b","b","b","b","b","b","b","b"]
Output:
Return 4, and the first 4 characters of the input array should be: ["a","b","1","2"].
Explanation:
Since the character "a" does not repeat, it is not compressed. "bbbbbbbbbbbb" is replaced by "b12".
Notice each digit has it's own entry in the array.
Note:
All characters have an ASCII value in [35, 126].
1 <= len(chars) <= 1000.
*/
/*
- for loop, track index, compare [i, i+1], count occurance
- no need to clena up rest
- return final last index
- measure number over 10
edge case:
1 char: show itself
no char or null: return
*/
class Solution {
public int compress(char[] chars) {
if (chars.length <= 1) {
return chars.length;
}
int index = 1, count = 1;
char c = chars[0];
// skip end case
for (int i = 0; i < chars.length - 1; i++) {
if (c == chars[i + 1]) {
count++;
continue;
}
// next char
c = chars[i + 1];
// closure of existing section
if (count != 1) {
index = assignChar(chars, index, count);
}
chars[index++] = c;
count = 1;
}
// end case
if (count != 1) {
index = assignChar(chars, index, count);
}
// index is increased by 1 after use, which just equals the actual length
return index;
}
private int assignChar(char[] chars, int index, int count) {
String s = String.valueOf(count);
for (char c : s.toCharArray()) {
chars[index++] = c;
}
return index;
}
}
```