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s0408_valid_word_abbreviation.go
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76 lines (61 loc) · 1.56 KB
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/*
https://leetcode.com/problems/valid-word-abbreviation
A string can be abbreviated by replacing any number of non-adjacent, non-empty
substrings with their lengths. The lengths should not have leading zeros.
For example, a string such as "substitution" could be abbreviated as (but not
limited to):
"s10n" ("s ubstitutio n")
"sub4u4" ("sub stit u tion")
"12" ("substitution")
"su3i1u2on" ("su bst i t u ti on")
"substitution" (no substrings replaced)
The following are not valid abbreviations:
"s55n" ("s ubsti tutio n", the replaced substrings are adjacent)
"s010n" (has leading zeros)
"s0ubstitution" (replaces an empty substring)
Given a string word and an abbreviation abbr, return whether the string matches
the given abbreviation.
A substring is a contiguous non-empty sequence of characters within a string.
*/
package solutions
import (
"strconv"
"strings"
"unicode"
)
func validWordAbbreviation(word string, abbr string) bool {
if len(abbr) > len(word) {
return false
}
var wi, ai int
word = strings.ReplaceAll(word, " ", "")
for wi < len(word) && ai < len(abbr) {
a, b := word[wi], abbr[ai]
if !unicode.IsDigit(rune(b)) {
if a != b {
return false
}
wi++
ai++
} else {
if b == '0' {
return false
}
cnt := []rune{}
for unicode.IsDigit(rune(b)) {
cnt = append(cnt, rune(b))
ai++
if ai > len(abbr)-1 {
break
}
b = abbr[ai]
}
n, err := strconv.Atoi(string(cnt))
if err != nil {
panic(err)
}
wi += n
}
}
return wi == len(word) && ai == len(abbr)
}