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1.py
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64 lines (62 loc) · 3.26 KB
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lon=input("请输入经度:")
lat=input("请输入纬度:")
scales = [500000, 250000, 100000, 50000, 25000, 10000]
# 定义计算地图分幅编号的函数
def calculate_map_sheet_number(lon, lat, scale):
# 计算1:100万地图分幅对应的行列初始值
lon=float(lon)
lat=float(lat)
row_100w = int((90 + lat)) // 4
col_100w = int((180 + lon)) // 6
col_letter_100w = chr(ord('A') + col_100w % 26) if col_100w >= 0 else chr(ord('A') + (26 + col_100w % 26))
row_str_100w = str(int(row_100w + 1)).zfill(2)
base_number = col_letter_100w + row_str_100w
if scale == 500000:
# 1:50万在1:100万基础上的行列细分计算
row_50w = (lat % 4) // 2312
col_50w = (lon % 6) // 3
return base_number + str(int(row_50w + 1)) + str(int(col_50w + 1))
elif scale == 250000:
# 1:25万在1:100万基础上的行列细分计算
row_25w = (lat % 4) // 1
col_25w = (lon % 6) // 1.5
return base_number + str(int(row_25w + 1)).zfill(2) + str(int(col_25w + 1)).zfill(2)
elif scale == 100000:
# 1:10万在1:100万基础上的行列细分计算
row_10w = (lat % 4) // (4 / 12)
col_10w = (lon % 6) // (6 / 12)
return base_number + str(int(row_10w + 1)).zfill(2) + str(int(col_10w + 1)).zfill(2)
elif scale == 50000:
# 1:5万在1:10万基础上的行列细分计算(先获取1:10万对应的行列基础)
row_10w = (90 + lat) // (4 / 12)
col_10w = (180 + lon) // (6 / 12)
row_5w = (lat % (4 / 12)) // (4 / 12 / 2)
col_5w = (lon % (6 / 12)) // (6 / 12 / 2)
col_letter_10w = chr(ord('A') + int(col_10w) % 26) if col_10w >= 0 else chr(ord('A') + (26 + int(col_10w) % 26))
row_str_10w = str(int(row_10w + 1)).zfill(2)
base_10w = col_letter_10w + row_str_10w
return base_10w + str(int(row_5w + 1)) + str(int(col_5w + 1))
elif scale == 25000:
# 1:2.5万在1:10万基础上的行列细分计算(先获取1:10万对应的行列基础)
row_10w = (90 + lat) // (4 / 12)
col_10w = (180 + lon) // (6 / 12)
row_2_5w = (lat % (4 / 12)) // (4 / 12 / 4)
col_2_5w = (lon % (6 / 12)) // (6 / 12 / 4)
col_letter_10w = chr(ord('A') + int(col_10w) % 26) if col_10w >= 0 else chr(ord('A') + (26 + int(col_10w) % 26))
row_str_10w = str(int(row_10w + 1)).zfill(2)
base_10w = col_letter_10w + row_str_10w
return base_10w + str(int(row_2_5w + 1)).zfill(2) + str(int(col_2_5w + 1)).zfill(2)
elif scale == 10000:
# 1:1万在1:10万基础上的行列细分计算(先获取1:10万对应的行列基础)
row_10w = (90 + lat) // (4 / 12)
col_10w = (180 + lon) // (6 / 12)
row_1w = (lat % (4 / 12)) // (4 / 12 / 8)
col_1w = (lon % (6 / 12)) // (6 / 12 / 8)
col_letter_10w = chr(ord('A') + int(col_10w) % 26) if col_10w >= 0 else chr(ord('A') + (26 + int(col_10w) % 26))
row_str_10w = str(int(row_10w + 1)).zfill(2)
base_10w = col_letter_10w + row_str_10w
return base_10w + str(int(row_1w + 1)).zfill(2) + str(int(col_1w + 1)).zfill(2)
return None
for scale in scales:
result = calculate_map_sheet_number(lon, lat, scale)
print("比例尺为{}时,地图分幅编号为: {}".format(scale,result))