question about the channel

[gopherbot]

by jikai507:

package main

import (
    "fmt"
)

func foo(ch chan string) {
    defer func() {
        ch <- "finish"
    }()

    // do some process
    // ...
}

func main() {
    ch := make(chan string)
    for i := 0; i <= 100; i++ {
        ch <- "start"
        go foo(ch)
    }

    var (
        msg        string
        allroutine int
        finished   int
    )
    // In this loop, I record two flags of goroutines.
    // If a routine start, a "start" message will emit 
    // to the channel.
    // If a routine finish, a "finish" message will emit
    // to the channel.
    // The variable allroutine always bigger than variable
    // finished because routine first start and finish
    // later.
    // If finished equal to the allroutine, it means
    // that all routines finished already. 
    for {
        msg = <-ch
        if msg == "start" {
            allroutine++
        }
        if msg == "finish" {
            finished++
        }
        fmt.Println("allroutine:", allroutine, "finished:", finished)
        if finished == allroutine {
            break
        }
    }
}


What does 'go version' print?
go v1.2.1

What happened?
deadlock...

What should have happened instead?
It will finished with the output "allroutine: 100 finished: 100".

Please provide any additional information below.

[cznic]

Comment 1:

The issue is in the code, not in Go: http://play.golang.org/p/nEovFS2P9N
#Invalid

[bradfitz]

Comment 2:

Status changed to Invalid.