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Merge pull request #1 from ankitdobhal/master
Updating my forked repo
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‎Basic-Scripts/Compress_the_string.py

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from itertools import groupby
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uncompressed = str(input("Enter string to compress: ")) # user input for string
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print(*[(len(list(value)), str(key)) for key, value in groupby(uncompressed)]) # logic to print occurence of values in string

‎Basic-Scripts/Geocoding and Reverse Geocoding/README.md

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### Geocoding and Reverse Geocoding
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#### This script takes an address and return its latitude and longitude.This process is called geocoding
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#### It can also perform the opposite operation that is take latitude, longitude and provide address.
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#### I have used the LocationIQ website's geocoding api inorder to solve this problem.
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#### In order to run this script you need to have a private token which is just a key for the api..
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#### To obtain your own private token create a *free account* at https://locationiq.com/ and replace my private token with yours.
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#### Remember, *don't share* your private token with anyone if you use your personal email for account creation.
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#### Install the dependencies by using:
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pip install -r requirements.txt
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#### An Example of the script in action:
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<img src="Sample.PNG" alt="Sample">
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‎Basic-Scripts/Geocoding and Reverse Geocoding/Sample.PNG

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‎Basic-Scripts/Geocoding and Reverse Geocoding/geocoding_and_reverse_geocoding.py

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import requests
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import sys
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# If you want your own private_token please refer the README file for this script.
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private_token = "<Your Private Token>"
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while True:
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choice = input(
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"Type G for geocoding , type R for reverse geocoding and type Q to quit the script:")
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print()
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# If the user choose to perform Geocoding
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if choice.upper() == 'G':
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# Base Url for geocoding
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url = "https://us1.locationiq.com/v1/search.php"
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address = input("Input the address: ")
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# Parameters for the geocoding url
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data = {
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'key': private_token,
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'q': address,
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'format': 'json'
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}
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response = requests.get(url, params=data)
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# To run only if we get success response
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if response.status_code == 200:
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latitude = response.json()[0]['lat']
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longitude = response.json()[0]['lon']
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print(f"The latitude of the given address is: {latitude}")
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print(f"The longitude of the given address is: {longitude}")
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print()
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else:
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sys.exit("Cant find what you where looking for")
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# If the user choose to perform Reverse Geocoding
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elif choice.upper() == 'R':
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# Base Url for reverse geocoding
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url = "https://us1.locationiq.com/v1/reverse.php"
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latitude_reverse = input("Enter the latitude: ")
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longitude_reverse = input("Enter the longitude: ")
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# Parameters for the reverse geocoding url
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data = {
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'key': private_token,
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'lat': latitude_reverse,
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'lon': longitude_reverse,
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'format': 'json'
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}
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response = requests.get(url, params=data)
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# To run only if we get success response
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if response.status_code == 200:
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address = response.json()['display_name']
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print(f"The address is: {address}")
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print()
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else:
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print("Cant find what you where looking for.")
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# If the user choose to Quit the program
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elif choice.upper() == 'Q':
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sys.exit("Thanks for using the script")
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# To make sure only valid input is provided
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else:
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print("Please make a valid choice")
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print()
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#Sample Input - Output:
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#If you choose Geocoding:
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#Address(Input): Rashtrapati Bhavan
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#Latitude(Output): 28.614458
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#Longitude(Output): 77.199594
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#If you choose Reverse-Geocoding:
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#Latitude(Input): 28.614458
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#Longitude(Input): 77.199594
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#Address(Output): Rashtrapati Bhavan, Rajpath, Presidential Estate, Chanakya Puri Tehsil, New Delhi, Delhi, 110004, India

‎Basic-Scripts/Geocoding and Reverse Geocoding/requirements.txt

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certifi==2020.6.20
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chardet==3.0.4
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idna==2.10
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requests==2.24.0
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urllib3==1.25.10

‎Basic-Scripts/README.md

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# Basic-Scripts
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Basic-Scripts is a collection of basic python scripts for newbies in python to understand basic concept of python programming.
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- Data Struture in python
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- Conditional
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- Loop
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- Exception Handling
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- Algorithms
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- OOP
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- Class
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- Object
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#Basic-Scripts
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Basic-Scripts is a collection of basic python scripts for newbies in python to understand basic concept of python programming.
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-Data Structure in python
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-Conditional
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-Loop
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-Exception handling
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-Algorithms
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-OOP
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-Class
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-Object
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‎Basic-Scripts/Rock_paper_scissor.py

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# -*- coding: utf-8 -*-
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"""
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Created on Mon Aug 17 14:24:23 2020
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@author: Gulshan
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"""
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# Function rock_paper_scissor--->
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def rock_paper_scissor(num1,num2,bit1,bit2):
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play_pos1=int(num1[bit1])%3 #Play Position For Player 1
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play_pos2=int(num2[bit2])%3 #Play Position For Player 2
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if(player_one[play_pos1]==player_two[play_pos2]):
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print("Draw")
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elif(player_one[play_pos1]=="Rock" and player_two[play_pos2]=="Scissor"):
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print("Player one wins!!")
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elif(player_one[play_pos1]=="Rock" and player_two[play_pos2]=="Paper"):
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print("Player two wins!!")
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elif(player_one[play_pos1]=="Paper" and player_two[play_pos2]=="Scissor"):
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print("Player two wins!!")
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elif(player_one[play_pos1]=="Paper" and player_two[play_pos2]=="Rock"):
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print("Player one wins!!")
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elif(player_one[play_pos1]=="Scissor" and player_two[play_pos2]=="Rock"):
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print("Player two wins!!")
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elif(player_one[play_pos1]=="Scissor" and player_two[play_pos2]=="Paper"):
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print("Player one wins!!")
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# Main Function To Execute Rock Paper Scissor
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if __name__ == '__main__':
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player_one={0:'Rock',1:'Paper',2:'Scissor'}
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player_two={0:'Paper',1:'Rock',2:'Scissor'}
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while(1):
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num1=input("Player one, Enter your choice ")
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num2=input("Player two, Enter your choice ")
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bit1=int(input("Player one, Enter the secret bit position "))
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bit2=int(input("Player two, Enter the secret bit position "))
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rock_paper_scissor(num1,num2,bit1,bit2)
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ch=input("Do you want to continue? y/n ")
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if(ch=='n'):
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break
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'''
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Output Implementation:
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Player one, Enter your choice 123
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Player two, Enter your choice 567
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Player one, Enter the secret bit position 0
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Player two, Enter the secret bit position 1
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Draw
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Do you want to continue? y/n y
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Player one, Enter your choice 012
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Player two, Enter your choice 234
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Player one, Enter the secret bit position 1
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Player two, Enter the secret bit position 2
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Player one wins!!
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Do you want to continue? y/n y
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Player one, Enter your choice 345
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Player two, Enter your choice 012
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Player one, Enter the secret bit position 0
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Player two, Enter the secret bit position 2
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Player one wins!!
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'''

‎Basic-Scripts/Simple_calculator.py

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operation = input('''
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Please type in the math operation you would like to complete:
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1 for addition
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2 for subtraction
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3 for multiplication
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4 for division
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''')
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num = int(input('Enter your first number: '))
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num2 = int(input('Enter your second number: '))
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if operation == '1':
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print('{} + {} = '.format(num, num2))
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print(num+num2)
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elif operation == '2':
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print('{} - {} = '.format(num, num2))
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print(num-num2)
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elif operation == '3':
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print('{} * {} = '.format(num, num2))
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print(num*num2)
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elif operation == '4':
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print('{} / {} = '.format(num, num2))
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print(num / num2)
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else:
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print('Wrong Input! Please Try Again')
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operation = input('''
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Please type in the math operation you would like to complete:
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1 for addition
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2 for subtraction
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3 for multiplication
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4 for division
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''')
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num = int(input('Enter your first number: '))
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num2 = int(input('Enter your second number: '))
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if operation == '1':
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print('{} + {} = '.format(num, num2))
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print(num+num2)
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elif operation == '2':
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print('{} - {} = '.format(num, num2))
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print(num-num2)
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elif operation == '3':
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print('{} * {} = '.format(num, num2))
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print(num*num2)
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elif operation == '4':
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print('{} / {} = '.format(num, num2))
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print(num / num2)
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else:
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print('Wrong Input! Please Try Again')
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=======
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"""The previous script becomes very boring for the user as he has to keep on typing just numbers and of wants to interact using
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simple english language he is unable to do so. Also the program terminates after one execution and if the user wants to keep on
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performing operations it becomes difficult.
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I have tried making a more simple and interactive calculator which allows the user to input any statement for performing the tasks. """
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def Calculator(num_1,num_2):
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#Executing the loop infinite times as we donot know how many times the user will want to run
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while(True):
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choice= input("Enter what you want to perform: ")
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print()
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#For Addition user can type any Sentence containing word related to it and will get the output but here we are checking only for the common words
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if ("addition" in choice) or ("add" in choice) or ("sum" in choice) or ("plus" in choice):
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sum = (num_1) + (num_2)
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print("Output....")
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print("Adding {} and {} results to {}".format(num_1,num_2,sum))
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print()
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#For Subtraction user can type any Sentence containing word related to it and will get the output but here we are checking only for the common words
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elif ("subtraction" in choice) or ("minus" in choice) or ("difference" in choice) or ("subtract" in choice):
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if( num_1 > num_2 ):
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diff = (num_1) - (num_2)
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print("Output....")
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print("Subtracting {} from {} results to {}".format(num_2,num_1,diff))
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print()
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elif( num_2 > num_1 ):
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diff = (num_2) - (num_1)
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print("Output....")
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print("Subtracting {} from {} results to {}".format(num_1,num_2,diff))
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print()
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#For Multiplication user can type any Sentence cpntaining word related to it and will get the output but here we are checking only for the common words
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elif ("multiplication" in choice) or ("product" in choice) or ("multiply" in choice):
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if(num_1==0 or num_2==0):
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print("Output....")
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print("Multiplying {} and {} results to 0".format(num_1,num_2))
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print()
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elif(num_1==1):
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print("Output....")
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print("Multiplying {} and {} results to {}".format(num_1,num_2,num_2))
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print()
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elif(num_2==1):
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print("Output....")
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print("Multiplying {} and {} results to {}".format(num_1,num_2,num_1))
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print()
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else:
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mul = (num_1) * (num_2)
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print("Output....")
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print("Multiplying {} and {} results to {}".format(num_1,num_2,mul))
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print()
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#For Division user can type any Sentence cpntaining word related to it and will get the output but here we are checking only for the common words
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elif("division" in choice) or ("divide" in choice) or ("quotient" in choice):
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if( num_1 > num_2 ):
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if(num_2==0):
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print("Output....")
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print("Error: Please try with some other values!")
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elif(num_1==0):
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print("Output....")
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print("Dividing {} from {} results to 0".format(num_1,num_2))
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print()
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else:
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div = (num_1) / (num_2)
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print("Output....")
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print("Dividing {} from {} results to {}".format(num_1,num_2,div))
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print()
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elif(num_1==0 and num_2==0):
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print("Infinity!")
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print()
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elif( num_2 > num_1 ):
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if(num_1==0):
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print("Output....")
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print("Error: Please try with some other values!")
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print()
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elif(num_2==0):
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print("Output....")
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print("Dividing {} from {} results to 0".format(num_1,num_2))
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print()
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else:
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div = (num_2) / (num_1)
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print("Output....")
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print("Dividing {} from {} results to {}".format(num_2,num_1,div))
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print()
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#For exiting the loop user can type any Sentence containing word related to it and it will exit from the loop but here we are checking for the common words
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elif ("exit" in choice) or ("stop" in choice) or ("return" in choice):
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break
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else:
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print()
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print("Operation not found: Please try again!")
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print()
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def main():
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print()
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print(" THIS IS A BASIC USER FRIENDLY CALCULATOR! ")
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print()
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print("You can type a sentence and interact.")
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print()
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#inputting two numbers at a time using the split function
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num_1,num_2 = input("Enter two numbers: ").split()
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num1=float(num_1)
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num2=float(num_2)
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#printing both the numbers
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print("Number 1 is: ",num_1)
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print("Number 2 is: ",num_2)
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print()
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Calculator(num_1,num_2)
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if __name__ == "__main__":
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main()

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