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symmetric-tree.rs
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#![allow(dead_code, unused, unused_variables)]
fn main() {
let root = Some(Rc::new(RefCell::new(TreeNode {
val: 1,
left: Some(Rc::new(RefCell::new(TreeNode {
val: 2,
left: Some(Rc::new(RefCell::new(TreeNode {
val: 3,
left: None,
right: None,
}))),
right: Some(Rc::new(RefCell::new(TreeNode {
val: 4,
left: None,
right: None,
}))),
}))),
right: Some(Rc::new(RefCell::new(TreeNode {
val: 2,
left: Some(Rc::new(RefCell::new(TreeNode {
val: 4,
left: None,
right: None,
}))),
right: Some(Rc::new(RefCell::new(TreeNode {
val: 3,
left: None,
right: None,
}))),
}))),
})));
assert!(Solution::is_symmetric(root));
}
struct Solution;
// Definition for a binary tree node.
#[derive(Debug, PartialEq, Eq)]
pub struct TreeNode {
pub val: i32,
pub left: Option<Rc<RefCell<TreeNode>>>,
pub right: Option<Rc<RefCell<TreeNode>>>,
}
impl TreeNode {
#[inline]
pub fn new(val: i32) -> Self {
TreeNode {
val,
left: None,
right: None,
}
}
}
use std::cell::RefCell;
use std::rc::Rc;
impl Solution {
pub fn is_symmetric(root: Option<Rc<RefCell<TreeNode>>>) -> bool {
if root.is_none() {
return true;
}
let mut has_more = true;
let mut v = vec![];
v.push(root.as_ref().unwrap().borrow_mut().left.take());
v.push(root.as_ref().unwrap().borrow_mut().right.take());
while has_more {
has_more = false;
let (mut i, mut j) = (0, v.len() - 1);
let mut v1 = vec![None; v.len() * 2];
while i < j {
match (v[i].as_ref(), v[j].as_ref()) {
(Some(x), Some(y)) => {
if x.borrow().val != y.borrow().val {
return false;
}
has_more = true;
v1[i * 2] = x.borrow_mut().left.take();
v1[i * 2 + 1] = x.borrow_mut().right.take();
v1[j * 2] = y.borrow_mut().left.take();
v1[j * 2 + 1] = y.borrow_mut().right.take();
}
(None, None) => {
v1[i * 2] = None;
v1[i * 2 + 1] = None;
v1[j * 2] = None;
v1[j * 2 + 1] = None;
}
_ => return false,
}
i += 1;
j -= 1;
}
v = v1;
}
true
}
}