Put basilisp bootstrap code at the beginning of lpyc? #1236
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If an lpyc file bootstraps basilisp if it's not bootstraped already, then you don't need to manually bootstrap basilisp? Any python module can load an lpyc file as if it was a pyc file if this is done? I'm just guessing in the dark. I can be wrong. |
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Replies: 2 comments 1 reply
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Throughout the library, Basilisp uses the term "bootstrap" to mean a couple of different things:
I'm not really sure which one you're referring to or how an The only code that knows about loading
I don't want to discourage people from submitting issues or proposing ideas to the project, but responding to issues like this takes up some of the limited time I have available to dedicate to the project. I understand that people aren't likely to know the details of the code base as intimately as I do, but I hope you can appreciate that "just guessing in the dark" does have a cost. Perhaps this might be better suited to be a discussion rather than an issue in the future. |
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I think python isn't going to cater to basilisp. Manual bootstrapping is the best we can do? Using Hy from Python says
Implicit names says
Hy language is more tightly coupled with python, and it still requires people to bootstrap hy runtime manually. I think adding |
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#1242 should be the answer to this discussion.