[patterns] Change if-case statement syntax to a more infix-like form. #2191
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Instead of: if (case [int x, int y] = json) return Point(x, y); The proposed syntax is now: if (json case [int x, int y]) return Point(x, y); This does *not* define an infix case *expression*. But it is more forward-compatible with that syntax if we decide to do that later. See #2181.
leafpetersen
reviewed
Apr 6, 2022
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Instead of:
if (case [int x, int y] = json) return Point(x, y);
The proposed syntax is now:
if (json case [int x, int y]) return Point(x, y);
This does not define an infix case expression. But it is more
forward-compatible with that syntax if we decide to do that later.
See #2181.