Is it possible to retain folder structure in outputdir?

[matthewoestreich]

Per the title...I am trying to retain the same structure in my output (so I suppose I just want to transpile/minify but not bundle into a single file), is this possible?

[matthewoestreich]

Sorry to bother, I figured it out.

This was for a react project - I had to change esbuild ./src to esbuild ./src/**.

Full Command: esbuild ./src/** --outdir=./dist --loader:.js=jsx

[devklick]

Is this still valid? I get an error when I try this.

Example structure:

src/
  lib/
    some-file.ts
  index.ts

Command:

esbuild ./src/** --outdir=./dist

Error:

Could not resolve "./src/lib"

Using esbuild v0.17.18

[evanw]

I'm assuming your shell is expanding ./src/** into ./src/lib here. If that's the case, then that's a problem with your shell, not with esbuild. Shell expansion happens before esbuild runs so esbuild doesn't even see ./src/** at all. You'll need to read your shell's documentation to figure out how to do glob expansion correctly. Either that or you can pass all of the files to esbuild manually.

[devklick]

Thanks @evanw, I realised it must be something like that after seeing an error:

It looks like you are trying to use glob syntax (i.e. "*") with esbuild. This syntax is typically
handled by your shell, and isn't handled by esbuild itself. You must expand glob syntax first
before passing your paths to esbuild.

It appears to work if I specify file types, e.g.

esbuild ./src/**/*.ts --outdir=./dist

[rlindgren]

nice. but can we exclude some files by glob pattern that match the entry glob?