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SC2004
Joachim Ansorg edited this page Nov 12, 2021
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echo $(($n + ${arr[i]}))echo $((n + arr[i]))The $ or ${..} on regular variables in arithmetic contexts is unnecessary, and can even lead to subtle bugs. This is because the contents of $((..)) is first expanded into a string, and then evaluated as an expression:
$ a='1+1'
$ echo $(($a * 5)) # becomes 1+1*5
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$ echo $((a * 5)) # evaluates as (1+1)*5
10The $ is unavoidable for special variables like $1 vs 1, $# vs #. It's also required when adding modifiers to parameters expansions, like ${#var} or ${var%-}. ShellCheck does not warn about these cases.
The $ is also required (and not warned about) when you need to specify the base for a variable value:
$ a=09
$ echo $((a + 1)) # leading zero forces octal interpretation
bash: 09: value too great for base (error token is "09")
$ echo $((10#a + 1))
bash: 10#a: value too great for base (error token is "10#a")
$ echo $((10#$a + 1))
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