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[3.12] gh-121657: Display correct error message for yield from outsid… #121769

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Merged
merged 1 commit into from
Jul 15, 2024
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[3.12] gh-121657: Display correct error message for yield from outsid… #121769

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5 changes: 5 additions & 0 deletions Lib/test/test_generators.py
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Original file line number Diff line number Diff line change
Expand Up @@ -2145,6 +2145,11 @@ def printsolution(self, x):
...
SyntaxError: 'yield' outside function

>>> yield from [1,2]
Traceback (most recent call last):
...
SyntaxError: 'yield from' outside function

>>> def f(): x = yield = y
Traceback (most recent call last):
...
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2 changes: 2 additions & 0 deletions Misc/NEWS.d/next/Core and Builtins/2024-07-13-12-27-31.gh-issue-121657.wgOYLw.rst
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@@ -0,0 +1,2 @@
Improve the :exc:`SyntaxError` message if the user tries to use
:keyword:`yield from <yield>` outside a function.
2 changes: 1 addition & 1 deletion Python/compile.c
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Expand Up @@ -6117,7 +6117,7 @@ compiler_visit_expr1(struct compiler *c, expr_ty e)
break;
case YieldFrom_kind:
if (!_PyST_IsFunctionLike(c->u->u_ste)) {
return compiler_error(c, loc, "'yield' outside function");
return compiler_error(c, loc, "'yield from' outside function");
}
if (c->u->u_scope_type == COMPILER_SCOPE_ASYNC_FUNCTION) {
return compiler_error(c, loc, "'yield from' inside async function");
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