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Looks like struct Foo(); is accepted and makes an expression Foo a value of that type, just like the regular form struct Foo; does. Since Foo() as an expression still doesn't work, this is kinda confusing, and anyway not intended as far as I know.
The text was updated successfully, but these errors were encountered:
Looks like
struct Foo();
is accepted and makes an expressionFoo
a value of that type, just like the regular formstruct Foo;
does. SinceFoo()
as an expression still doesn't work, this is kinda confusing, and anyway not intended as far as I know.The text was updated successfully, but these errors were encountered: